Hello. I'm traying to generate un HDL code from matlab user-definded function algorithm and got an error about function specialisation that I didn't understand.

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Bouchra BENDAHANE 2021-9-2

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https://ww2.mathworks.cn/matlabcentral/answers/1445194-hello-i-m-traying-to-generate-un-hdl-code-from-matlab-user-definded-function-algorithm-and-got-an

评论： Bouchra BENDAHANE 2021-9-8

this is the error msg that I got :

The function 'AppDec_Fun2' contains persistent variables 'dataAppFun2' and has specialization 'AppDec_Fun2_s1' associated with it. Function specializations containing persistent variables are not supported for fixed-point conversion. Consider rewriting your algorithm such that it does not use persistent variables within functions that require specialization.

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Bouchra BENDAHANE 2021-9-3

编辑：Walter Roberson 2021-9-3

在 MATLAB Online 中打开

Thank you for your answer. I understood that the output of the called function shoudn't be inside any loop but I'm working with signals and wich impose the use of loop inorder to generate output signal.

this is my function code:

function [Output_vect,output_ENB] =AppDec_Fun2(Input_vect,input_ENB)
LFD1=-0.0106;
LFD2=0.0329;
LFD3=0.0308;
LFD4=-0.1870;
LFD5=-0.0280;
LFD6=0.6309;
LFD7=0.7148;
LFD8=0.2304;
Output_vect=zeros(1,8);
persistent dataAppFun2;
if isempty(dataAppFun2)
    dataAppFun2=zeros(1,8);  
end
if input_ENB==1
   j=1;
        for i=1:1:length(Input_vect)
                    dataAppFun2(1)=dataAppFun2(2);
                    dataAppFun2(2)=dataAppFun2(3);
                    dataAppFun2(3)=dataAppFun2(4);
                    dataAppFun2(4)=dataAppFun2(5);
                    dataAppFun2(5)=dataAppFun2(6);
                    dataAppFun2(6)=dataAppFun2(7);
                    dataAppFun2(7)=dataAppFun2(8);
                    dataAppFun2(8)=Input_vect(i);
                  if mod(i,2)==0
                  Output_vect(j)=dataAppFun2(1)*LFD1+dataAppFun2(2)*LFD2+dataAppFun2(3)*LFD3+dataAppFun2(4)*LFD4+dataAppFun2(5)*LFD5+dataAppFun2(6)*LFD6+dataAppFun2(7)*LFD7+dataAppFun2(8)*LFD8; 
                   j=j+1;
                  end
        end 
        output_ENB=1;
else
     output_ENB=0;
end           

Walter Roberson 2021-9-3

Memory Store perhaps ?

Or you could probably avoid the problem by coding the function in fixed-point yourself, so that it did not need to be specialized to convert from double to fixed point.

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