How to decompose 3d array to 3 matrices

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RADWAN A F ZEYADI
RADWAN A F ZEYADI 2021-10-25
编辑： James Tursa 2021-10-25
Hi every one
i have a 3d array with dimension 51*71*3 and i want to obtain column vector 153*1
d=(51*71*3)
n=d(:,:,1) so now 51*71
r=d(:,:,2) becomes 51*71
c=data(:,3) becomes51*71
so now b=[n;r;c] 153*71
but i need153*1 instead
how can i obtain this vector
thanks in advance

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回答（1 个）

Jan
Jan 2021-10-25
Ran in:
x = rand(51, 71, 3);
v = reshape(x(:, 27, :), [], 1);
size(v)
ans = 1×2
153 1
  2 个评论
RADWAN A F ZEYADI
RADWAN A F ZEYADI 2021-10-25
thanks but i mean 153 *1 of original d (153*71) i dont need to generate random vector
James Tursa
James Tursa 2021-10-25
编辑：James Tursa 2021-10-25
@RADWAN A F ZEYADI The random vector was just to generate sample data of the same size as your problem. Jan is not suggesting that you need to use rand( ) in your code. E.g., using your d variable:
v = reshape(d(:, 27, :), [], 1);

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