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searching first two consecutive ones and set to 0

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VASUNDHARA V
VASUNDHARA V 2022-2-25
评论： VASUNDHARA V 2022-2-25
y=[1 1 1 1 1 1 1 1 1 1 1]
i want to search for first two consecutive ones everytime and allocate them 0
like this
y=[0 0 1 1 1 1 1 1 1 1 1]

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采纳的回答

Arif Hoq
Arif Hoq 2022-2-25
编辑：Arif Hoq 2022-2-25
Ran in:
try this:
y=[1 1 1 1 1 1 1 1 1 1 1];
idx=y(1:2);
b=find(y(idx));
if y(b)==1
y(b)=0;
end
disp(y)
0 0 1 1 1 1 1 1 1 1 1
  3 个评论
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Jan
Jan 2022-2-25
Ran in:
This does not work, if y does not start ith two 1 values:
y=[0 0 1 1 1 1 1 1 1 1 1]
y = 1×11
0 0 1 1 1 1 1 1 1 1 1
idx=y(1:2);
b=find(y(idx));
Array indices must be positive integers or logical values.
if y(b)==1
y(b)=0;
end
disp(y)

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更多回答（1 个）

Jan
Jan 2022-2-25
编辑：Jan 2022-2-25
Ran in:
y = [0 0 1 1 1 1 1 1 1 1 1];
index = strfind(y, [1, 1]);
if any(index)
y(index(1):index(1)+1) = 0;
end
y
y = 1×11
0 0 0 0 1 1 1 1 1 1 1
  3 个评论
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Jan
Jan 2022-2-25
As fas as I understand, this would be working then:
if all(y(1:2) == 1)

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