how can I plot y = (cos(t-2)/4)(rect(t+1)/6 )?

Question

SaiRevan Potharaju 2022-8-3

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1773275-how-can-i-plot-y-cos-t-2-4-rect-t-1-6

编辑： Jan 2022-8-3

y = [(1-cos(0.25*(t-2).^2))*rect(t+1,6)]

is it correct way to write tht code ?

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显示 -1更早的评论隐藏 -1更早的评论

Jan 2022-8-3

编辑：Jan 2022-8-3

The brackets [ and ] are the concatenation operator in Matlab. What do you concatenate?

The shown code does not allow to plot anything, so how could it be correct?

What is "rect"? Why do you convert "rect(t+1)/6" to "rect(t+1,6)" ?

"cos(t-2)/4" differs from "1-cos(0.25*(t-2).^2)" also. Very strange.

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Answer 1

Adam Danz 2022-8-3

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1773275-how-can-i-plot-y-cos-t-2-4-rect-t-1-6#answer_1020530

is it correct way to write tht code ?

The line of code looks functional without knowing any other details including what rect is.