extract all values within a if loop to be stored to be used in a figure

Question

Adil Saeed 2022-8-17

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1780760-extract-all-values-within-a-if-loop-to-be-stored-to-be-used-in-a-figure

评论： Jan 2022-8-17

    %Source Level
    if 0<i && i<=PnC(1)
        SL = 200;
    else
        SL = 210;
    end

This is the relevant code, i want both vaues of SL to be stored and used in a plot, as at the moment only the value of 210 is being stored. the if statement is a time period to when SL = 200, and after this period the remaining part of the event is of SL = 210.

%Time

T = 5400;

INT = 900;

TINT = 0:INT:T;

%Number of Positions and Impacts

In = [50, 60, 75, 375, 420, 360];

Pn = sum(In);

PnC = cumsum(In);

n = numel(TINT);

TVpieces = cell(1, n-1);

for iter = 1:n-1

Inc = INT/In(iter);

TVpieces{iter} = TINT(iter):Inc:(TINT(iter+1)-Inc);

end

TV = [TVpieces{:}];

for i = 1:Pn

%Source Level

if 0<i && i<=PnC(1)

SL = 200;

else

SL = 210;

end

%RECEIVE LEVEL MODEL

figure

% set(plot(TV,RL,'.'),'markersize',3)

% hold on;

set(plot(TV,SL,'.'),'markersize',3)

% hold on;

% set(plot(TV,RLS,'.'),'markersize',3)

xlabel('Time (s)')

ylabel('Decibels (dB)')

legend({'Individual Strike Recieve Level (dB re μPa^2s)','Individual Strike Source Level (dB re μPa^2s-m)'},'Location','north')

%'Cumalative SEL Level (dB re μPa^2s)'

When we run this code, the graph produced only plots the values for SL at 210, whereas during the condition of if 0<i && i<=PnC(1) i would like the plot to be of 200, once this is complete SL is 210 based on its time. the graph should show 2 straight horizontal lines, when SL = 200 between 0<i && i<=PnC(1) and SL = 210 between PnC(1)<i && PnC(end).

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Jan 2022-8-17

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1780760-extract-all-values-within-a-if-loop-to-be-stored-to-be-used-in-a-figure#answer_1027960

编辑：Jan 2022-8-17

在 MATLAB Online 中打开

The code overwrite SL in each iteration. Store it as a vector instead:

SL = zeros(1, Pn)
for i = 1:Pn
    if 0<i && i <= PnC(1)
        SL(i) = 200;
    else
        SL(i) = 210;
    end
end

or shorter:

SL = 200 + 10 * ((1:Pn) <= PnC(1));
% or
SL = repmat(200, 1, Pn);
SL(PnC:Pn) = 210;

Note that for the index i running from 1 to Pn, checking 0 < i is useless.

2 个评论
显示无隐藏无

Adil Saeed 2022-8-17

thank you, much appreciated. about your last note, checking for 0 < i how would you change it?

Jan 2022-8-17

I'd simply omit the test of 0 < i, because this cannot happen in the loop.

请先登录，再进行评论。

extract all values within a if loop to be stored to be used in a figure

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

采纳的回答

2 个评论
显示无隐藏无

更多回答（0 个）

另请参阅

类别

标签

Community Treasure Hunt

extract all values within a if loop to be stored to be used in a figure

0 个评论 显示 -2更早的评论隐藏 -2更早的评论

采纳的回答

2 个评论 显示 无隐藏 无

更多回答（0 个）

另请参阅

类别

标签

Community Treasure Hunt

WeChat

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

2 个评论
显示无隐藏无