Find a number and range of group of the same number

a = [1 1 1 1 1 1 1 2 2 2 2 3 3 3 3 1 1 2 2 1 1 3 3 3 3 3 1 1 1 2 2 2];
[b, n, idx] = RunLength(a);
idxR   = [idx(:), idx(:) + n(:) - 1];
idxR = 9×2
     1     7
     8    11
    12    15
    16    17
    18    19
    20    21
    22    26
    27    29
    30    32
ub     = unique(b);
result = splitapply(@(c) {c}, idxR, b(:));
result = 3×1 cell array
    {4×2 double}
    {3×2 double}
    {2×2 double}
result{ub(1)}  % Ranges, where e.g. ub(1), which equals 1, occurs:
ans = 4×2
     1     7
    16    17
    20    21
    27    29

If you do not have a C-compiler, use RunLength_M from the same submission.

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Answer 2

Bruno Luong 2022-11-14

0
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1850528-find-a-number-and-range-of-group-of-the-same-number#answer_1099293

编辑：Bruno Luong 2022-11-14

在 MATLAB Online 中打开

A= [1 1 1 1 1 1 1 2 2 2 2 3 3 3 3 1 1 2 2 1 1 3 3 3 3 3 1 1 1 2 2 2 ];
[u,~,G]=unique(A);
n = length(u);
for g=1:n
    i = find(G==g);
    j = find([true; diff(i)>1; true]);
    start=i(j(1:end-1));
    stop=i(j(2:end)-1);
    m = length(start);
    fprintf('value=%g, %d intervals\n', u(g), m);
    fprintf('\t(%d:%d)\n', [start, stop]');
end
value=1, 4 intervals
	(1:7)
	(16:17)
	(20:21)
	(27:29)
value=2, 3 intervals
	(8:11)
	(18:19)
	(30:32)
value=3, 2 intervals
	(12:15)
	(22:26)