precision problem when creating a time vector

3 次查看（过去 30 天）

显示更早的评论

Benjamin Brammer 2022-11-29

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1866548-precision-problem-when-creating-a-time-vector

评论： Benjamin Brammer 2022-11-29

采纳的回答： Stephen23

在 MATLAB Online 中打开

Hello!

Ia have come across a very strange phenomena:

When you create the following vectors (time vectors) there seems to be a precision problem, allthough I don't understand why:

t1 = 0:.00001:0.0010; %time vector for a pulse 10µs step
t2 = 0.00101:.00001:0.015; % time vector for a discharge 10µs step
t3 = [t1, t2]; %resulting time vector for plot

Normally, I would expect, that if you try to find the index of t3 at the time of 4.5ms (0.0045) this should be no problem. But if you run the code

find(t3 == 0.0045)

ans = 1×0 empty double row vector

you will get no return, as for some reason matlab is not hitting the exact 4.5ms in the vector.

Furthermore if you try to find the deviation by the following code line:

t3(451) - 0.0045 % 451 is the index for 4.5ms
ans = 8.6736e-19

you can see that there is a very small deviation from the exact value. But this should normally not be the case. At least for my understanding. Or where is the mistake here?

kind regards

Benjamin

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Jan 2022-11-29

@Stephen23: Please move this to the section of answers.

@Benjamin Brammer: "Or where is the mistake here?" Follow Stephen's links. You observe the expected behavior of floating point arithmetics with a limited precisions. This is explain in the first lesson of courses for numerical maths and you find it on the first pages of text books for this topic.

"Why is 0.1 + 0.2 ~= 0.3" is a frequently asked question. Welcome to the world of numerical maths.

请先登录，再进行评论。

请先登录，再回答此问题。