Hello, how can I calculate the row and column by inserting a 3D matrix using this equation
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clc
clear all
close all
xm= [5 5 5 5;5 -4 -3 -2;5 -1 0 1;5 2 3 4]
n=length(xm);
[cf] =coherence_factor(xm,n)
function [cf] = coherence_factor(xm,n)
for i=1:4;
n=length(xm(i,:));
%%%%%%%%%%%%%%%%%%%% equation %%%%%%%%%%%%%%%%%%%
cf(i)=(abs (sum(xm(i,:))).^2) / (n* sum(abs(xm(i,:).^2)));
end
CF=cf(i);
end
3 个评论
Jan
2023-3-1
@hisham mohammed: You define n as input argument, but overwrite it by the same value in each iteration. Of course all xm(i,:) have the same length. So use this before the loop:
m = size(xm, 2);
The line CF=cf(i); is useless, because CF is not replied. Currently the output is a vector. It is not clear how you want to expand ot to 3D.
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