0 个投票

Hi , its the first time I'm using Matlab, I would like to know how can i run this function
function [ x,fx ,iter,x_vett]=gradiente(f,grad,x0,maxiter)
considering that f is a function of more variables, grad is a number (gradient of f), x0 is a vector and maxiter the maximum number if iterations. I use the command
[ x,fx ,iter,x_vett]=gradiente(f,grad,x0,maxiter)
with the f=@(x) 3*x(1)+2x(2) but it displays an error : "too many input arguments"

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Jan
Jan 2015-6-28
Please post a complete copy of the error message and the line, which causes the error.
Geoff Hayes
Geoff Hayes 2015-6-28
Diego - which line of code is generating the error? The too many input arguments message is telling you that you are supplying too many input parameters to one of your functions. There probably isn't an error with gradiente but we need to know how the input function handle f is being used within that function. Perhaps it is being called with a second input parameter (i.e. two input parameters are being passed in whereas your code is assuming a single 2 element vector input is being used).
Note also the typo with your f. You are missing a multiply (?) between the 2 and x
f=@(x) 3*x(1)+2*x(2)
DIEGO FOSSO
DIEGO FOSSO 2015-6-28
This is the code of the function:
function [ x,fx ,iter,x_vett]=gradiente(f,grad,x0,toll,maxiter)
x=x0;
fx=feval(f,x(1),x(2));
d=-feval(grad,x(1),x(2));
err=norm(d);
iter=0;
x_vett=[x];
while (err>toll) & (iter <=maxiter)
alpha=linesearch(f,grad,x,d);
x=x+alpha*d;
x_vett=[x_vett,x];
d=-feval(grad,x(1),x(2));
err=norm(d);
iter=iter+1;
end
fx=feval(f,x(1),x(2));
if (err>toll) & iter>maxiter
error('Hai superato il numero max di iterazioni!!!')
end
This are my inputs and the errors
>> f=@(x) [2*x(1)+3*x(2)];
>> x0=[1,2];
>> grad=3;
>> maxiter=10;
>> toll=0.5;
>> [ x,fx ,iter,x_vett]=gradiente(f,grad,x0,maxiter)
Error using @(x)[2*x(1)+3*x(2)]
Too many input arguments.
Error in gradiente (line 8)
fx=feval(f,x(1),x(2));
DIEGO FOSSO
DIEGO FOSSO 2015-6-28
This is the funtion "linesearch" (if you want to try to run it)
function alpha=linesearch(f,grad,x,d)
gamma=0.1;
sigma=1/4;
alpha=1;
alphamin= 10^(-3);
xnew=x+alpha*d;
while feval(f,xnew(1),xnew(2))>feval(f,x(1),x(2))+... % I cond. di Wolfe
gamma*alpha*feval(grad,x(1),x(2))'*d & alpha>alphamin
alpha=sigma*alpha;
xnew=x+alpha*d;
end

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Thorsten
Thorsten 2015-6-28
编辑：Thorsten 2015-6-29

0 个投票

You have defined your function f with a single argument x but you call it with two arguments x(1) and x(2) in using fx=feval(f,x(1),x(2)); instead, use
fx=feval(f,x);

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DIEGO FOSSO
DIEGO FOSSO 2015-6-29
How can I define a function of two variables? I can't change fx = feval (f, x(1), x(2)) because it's not a code written by me

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Geoff Hayes
Geoff Hayes 2015-6-28

0 个投票

Diego - when I run the above code, I observe the same error. This is because your anonymous function f is defined as a function that accepts a single input parameter
f=@(x) [2*x(1)+3*x(2)];
In gradiente, the following call is made against this function using feval
fx=feval(f,x(1),x(2));
and so we are passing two input parameters to a function that is expecting one (and so the error makes sense).
It is probably easier to just modify the function f to accept to input parameters as
f=@(x,y) [2*x+3*y];
and you should be able to proceed from there.
I did notice that the code in gradiente is assuming that the input grad is a function too
d=-feval(grad,x(1),x(2));
yet you are passing in the constant three. This will lead to the following error here (and in linesearch)
Error using feval
Argument must contain a string or function_handle.
Error in gradiente (line xxx)
d=-feval(grad,x(1),x(2));
How should grad be written as a function?

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