0 个投票

I have a matrix A=[A0 A1]
A0 and A1 are [M x L] matrix and A is [M x LNt]
Another matrix B=[A0A0' A1A1']
B is M X M matrix and Ak' is [M x (p-L)] matrix
I have obtained A, but couldn't get B as dimensions vary
I have taken M=128,L=16,Nt=2,Nr=1,p=M/Nt=64
This is mimo ofdm project " Joint estimation of cfo,i/q imbalance and channel response of mimo ofdm sysytems"

8 个评论
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Jan
Jan 2012-2-22
If it is urgent, I suggest to improve the question. We have to guess to much details, e.g. what is an "M X L matrix"? I guess this means [M x L]. But I have no idea about "M X LNt" or "[A0A0' A1A1']" - does the quote mean a transponation here? And what is "Ak'"?
How did you obtain A and what is the problem at obtaining B?
Does the last sentence provide any necessary information?
Please use dots to separate the sentences. The more time you invest to make the qeustion as easy to understand as possible, the high is the motivation to create a meaningful answer.
Janet
Janet 2012-2-22
Pls have a look at my base paper
http://www.scribd.com/doc/48495968/My-Base-Paper in 3rd page
I am beginner in matlab and doing a project in communication
Pls help with it
Walter Roberson
Walter Roberson 2012-2-22
http://www.mathworks.com/matlabcentral/answers/29922-why-your-question-is-not-urgent-or-an-emergency
Janet
Janet 2012-2-22
M xLNt means 128x32 matrix
A is a matrix having elements [ A0 A1.....ANt-1 ]
since my Nt is 2, A becomes A=[A0 A1]
B=[A0A0' A1A1']
Ak' means A0 to Ant-1
Janet
Janet 2012-2-22
i am a newbie here Walter..sorry for using urgent word
Honglei Chen
Honglei Chen 2012-2-22
You said you have A, so do you have A0 and A1? I don't think a lot of people will volunteer to read the paper for you so you may want to frame your question to be very specific and relevant to MATLAB.
Janet
Janet 2012-2-22
A is a matrix with elements A0 and A1
A=[A0 A1]
Janet
Janet 2012-2-22
I have formed matrix A:
A0=randn(M,L);
A1=randn(M,L);
A=horzcat(A0,A1);

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Honglei Chen
Honglei Chen 2012-2-22

0 个投票

OK, the question becomes more concrete now. Since you have A0 and A1, then you can do
A = [A0 A1];
B = [A0*A0' A1*A1'];
What is the dimension issue you mentioned in the question?

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