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Janet
Janet 2012-2-22
编辑: Cedric 2013-10-20
I have a matrix A=[A0 A1]
A0 and A1 are [M x L] matrix and A is [M x LNt]
Another matrix B=[A0A0' A1A1']
B is M X M matrix and Ak' is [M x (p-L)] matrix
I have obtained A, but couldn't get B as dimensions vary
I have taken M=128,L=16,Nt=2,Nr=1,p=M/Nt=64
This is mimo ofdm project " Joint estimation of cfo,i/q imbalance and channel response of mimo ofdm sysytems"
  8 个评论
Janet
Janet 2012-2-22
A is a matrix with elements A0 and A1
A=[A0 A1]
Janet
Janet 2012-2-22
I have formed matrix A:
A0=randn(M,L);
A1=randn(M,L);
A=horzcat(A0,A1);

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采纳的回答

Honglei Chen
Honglei Chen 2012-2-22
OK, the question becomes more concrete now. Since you have A0 and A1, then you can do
A = [A0 A1];
B = [A0*A0' A1*A1'];
What is the dimension issue you mentioned in the question?

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