Polynom of phi -> derivate to [mm/rad] and [mm/rad^2]

1 次查看(过去 30 天)
Hello everybody, I need your help!
I have a huge dataset for an ellipse.
Column 1 = degree from 0° -> 360°
Column 2 = radius (I define it as distance from the center) -> s [mm]
In the end I would like to plot the angular velocity [mm/rad] and the angular acceleration [mm/rad^2]. Therefor I used polyfit to get a function for the radius in dependency of degree -> s(°) with the unit [mm]
Now I would like to diff this function to get the angular velocity [mm/rad] and the angular acceleration [mm/rad^2].
The math looks like this:
s_dot = ds/dt = ds/dphi * dphi/dt = ds/dphi * omega
I have already tried it in several ways, but I’m not able to succeed.
Many thanks in advance!
Cheers
Christian
  5 个评论
Christian
Christian 2017-1-19
Yes, you might be right! 'radial velocity' is what I mean. My ellipse is on a shaft which rotates. So the change of the radius causes a radial velocity for all points on the brink of the ellipse.
You could compare this problem to a camshaft where the velocity of the points on the brink of a cam looks like this:
Christian
Christian 2017-1-19
编辑:Christian 2017-1-19
I solved it!
s_strich=gradient(s, Shaft_deg).*(180/pi)
I used the diff function all the time, but the gradient function is what I was looking for. Simple as that :)

请先登录,再进行评论。

回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Mathematics 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by