Convert 24 bit 2D array to 8 bit 3D (RGB) array

2 次查看(过去 30 天)
Hello all,
I am reading in data from a camera sensor, and it is stored as a 32-bit 2D array. Here, the first 8 bits correspond to Red, the next 8 bits to Green, and so on. I want to split this 2D array (of size (a,b)) to a 3D array (a,b,3), where each element in the array is 8-bit long. I am currently doing this as follows:
[r c]= size(img);
IMG = zeros(r,c,3);
for i = 1:r
for j = 1:c
temp = dec2bin(img(i,j),24);
IMG(i,j,1) = bin2dec(fliplr(temp(1:8)));
IMG(i,j,2) = bin2dec(fliplr(temp(9:16)));
IMG(i,j,3) = bin2dec(fliplr(temp(17:24)));
end
end
figure, imshow(IMG(:,:,1))
figure, imshow(IMG(:,:,2))
figure, imshow(IMG(:,:,3))
This takes a very long time to compute (~ 20 minutes) for the large images that I am currently using.
Is there a more efficient way of doing this?
Thanks in advance!

回答(2 个)

Walter Roberson
Walter Roberson 2012-3-27
IMGB = reshape( typecast(img, 'uint8'), [4, size(img)]);
Then row 1 will correspond to one of the bands, row 2 to another, etc..
You might need to do a bit of work to figure out which row is which.
  2 个评论
Jan
Jan 2012-3-27
If speed matters (does it ever?), James' typecast function is recommended: http://www.mathworks.com/matlabcentral/fileexchange/17476-typecast-and-typecastx-c-mex-functions
Geoff
Geoff 2012-3-27
Good point. I use MatLab for prototyping speed, not execution speed.

请先登录,再进行评论。


Geoff
Geoff 2012-3-27
Try using bitwise operators like you would in C. These handily operate on a matrix, so you can split out your components like so:
[r c]= size(img);
IMG = zeros(r,c,3);
IMG(:,:,1) = uint8(bitand(img, 255))
IMG(:,:,2) = uint8(bitand(bitshift(img,-8), 255));
IMG(:,:,3) = uint8(bitand(bitshift(img,-16), 255));
  3 个评论
Jan
Jan 2012-3-27
I assume that a division is faster than the bit-shifting.
Geoff
Geoff 2012-3-27
Well, I come from a C background so I just assumed that those functions share some kind of parallel. =) If division in MatLab is faster, that doesn't say much about the bitshift function!

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Numeric Types 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by