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How to solve the 'Index exceeds number of subplots' error?

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Emrys
Emrys 2018-1-23
评论： the cyclist 2020-9-14
Hi guys, I have to solve this problem: I have this code:
for p=1:22
subplot(5,2,p)
end
It gives me the following error 'Index exceeds number of subplots', how can I solve it?
  2 个评论
the cyclist
the cyclist 2020-9-14
Please add more detail to this question. Or, better yet, ask a brand-new question the fully explains what you want to know.

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采纳的回答

Jan
Jan 2018-1-23
编辑：Jan 2018-1-23
If you ask subplot to draw an 11th subplot on a 5 x 2 grid, you cannot expect that it is such smart to create a new figure and reset the index to 1. Matlab cannot simply do what you mean. But you can write a corresponding command.
for p = 1:22
pp = mod(p - 1, 10) + 1;
if pp == 1
FigH = figure;
end
subplot(5, 2, pp, 'Parent', FigH);
...
end

更多回答（1 个）

the cyclist
the cyclist 2018-1-23
编辑：the cyclist 2018-1-23
The way you have defined the subplot layout, you have a 5-by-2 grid of subplots, which is a total of 10 subplot locations. But you are trying to place 22 subplots.
You need to increase the number of subplot locations (maybe use 5x5?), or decrease the number of subplots.
  1 个评论
Emrys
Emrys 2018-1-23
编辑：Emrys 2018-1-23
Is there any way of automatically creating new layouts? what I was expecting were three figures, 2 with 10 elements and one with 2 .

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