How to take the 8th bit in lsb

1 次查看（过去 30 天）
Swati Nagpal
Swati Nagpal 2018-5-31
回答： Walter Roberson 2018-6-1
I am applying LSB for image steganography and I have got the binary representation of an rgb image i. e. 10001010 but I m not getting any idea of how to use the 8th bit to hide data in it anybody plz help me.
  3 个评论
显示 1更早的评论
Jan
Jan 2018-5-31
The readers cannot guess, what "binary representation of an rgb image i. e. 10001010" exactly is. Is this a logical vector, a decimal number or a character vector? Did you search in the forum for "lsb steganography" already? You will find a lot of corresponding threads.
I strongly recommend to remove the "ASAP" from the question. Pushing the readers is counterproductive, because it sounds impolite.
Swati Nagpal
Swati Nagpal 2018-6-1
the binary representation of 10001010 is just an example from my side. The thing is i have got uptothe binary representation of the image and now i have to take the 8th least bit of it to apply the lsb technique. i want a code for it so please help me in this.

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

Walter Roberson
Walter Roberson 2018-6-1
You can use bitset() and bitget() .
To extract the lsb you can use mod(YourImage,2) . To set new lsb you can do
YourImage - mod(YourImage,2) + NewLSBValue

类别

在 Help Center 和 File Exchange 中查找有关 Encryption / Cryptography 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by