What would happen if the time for function execution is bigger that the t.Period using timer object

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John Rebbner 2018-10-17

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评论： Jan 2018-10-17

Hello, guys! I am wondering what would happen if I use a timer object to execute a program, but the period of the timer is smaller than the time required for the program execution.

For example:

t = timer;
t.TimerFcn = @(~,thisEvent)disp([thisEvent.Type ' executed '...
     datestr(thisEvent.Data.time,'dd-mmm-yyyy HH:MM:SS.FFF')]);
t.Period = 10;
t.ExecutionMode = 'fixedRate';
start(t)

and the time for the function execution takes, let's say 20 sec. Are there any methods which send us a message that the program could not be done, because it requires more time? Thank you!

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Answer 1

Guillaume 2018-10-17

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It's completely documented in the timer documentation and the behaviour will depends on what you set the BusyMode property to. It can drop the missed task, queue it, or simply error.

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Jan 2018-10-17

在 MATLAB Online 中打开

+1. Exactly. And you can check manually what happens:

t.TimerFcn = @myTask;
t.BusyMode = 'drop';   % or 'queue' or 'error'
...
function myTask(TimerH, Event)
disp([Event.Type ' executed ' ...
      datestr(Event.Data.time,'dd-mmm-yyyy HH:MM:SS.FFF')]
pause(11)
end