how to form a indexed matrix?

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评论： Jan 2018-11-26

采纳的回答： Jan

Row matrix

A=[0 2 3; 3 2 1; 2 3 1]

Column

B= 2

Index matrix

C=[10 20 50; 60 80 90 ; 20 60 40]

Result expected

i would first select colum As 2

And look for the values of C

Depending on row number from A

D=[0 80 60; 60 80 20; 80 60 20]

Jan 2018-11-26

The quetsion is not really clear. With some bold guessing:

A  = [1 2 3; 3 2 1; 2 3 1];
B  = 2;
C  = [10 20 50; 60 80 90 ; 20 60 40];
CB = C(:, B);  
D  = CB(A)

Can u suggest me something for zero terms

Jan 2018-11-26

D = zeros(size(A));
m = (A ~= 0);
D(m) = CB(A(m));

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