Create aa difficult matrix in a loop

6 次查看(过去 30 天)
Hey all,
in general I dont have much problems creating a matrix with a loop, but I cant see the pattern here.
If loop is not the right answer here, maybe you could give me a hint for something else?
Thx !
  2 个评论
Jan
Jan 2019-1-4
编辑:Jan 2019-1-4
There is no "if loop" in any programming language I know. You showed 3 different matrices. There is an infinite number of methods to create these 3 matrices with a certain number of input arguments. So what is the actual definition and what are the parameters for the 3 examples? There are some white and some light blue cells. Please do not let the readers guess the details.
Tim
Tim 2019-1-4
Oh, I am sorry. I will edit right away.

请先登录,再进行评论。

采纳的回答

Jan
Jan 2019-1-4
编辑:Jan 2019-1-4
With some bold guessing:
n = 2;
R = -ones(n+1, n, n+1);
v = 1:n+1;
for k = v
R(v(v ~= k), :, k) = eye(n);
end
R = reshape(R, n+1, n*n+n)

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by