Counting the number of a specific word in text.

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pawlo392
pawlo392 2019-5-13
评论： Guillaume 2019-5-13
I want to create a program, tah will count specific words in text. I wrote this:
filename='File name : ';
word= 'Searched word : ';
A=input(filename,'s');
B=input(word,'s');
count=0;
fid=fopen(filename);
C=textscan(fid,'%/s');
for i=1:lenght(C{1})
words=char(C{1}(i));
words=strrep(words,'.','');
words=strrep(words,',','');
if (strcmp(words,word))
count=count+1;
end
end
But this program isn't working.
I got:
Error using textscan
Invalid file identifier. Use fopen to generate a valid file identifier.
Error in count_word (line 7)
C=textscan(fid,'%/s'
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pawlo392
pawlo392 2019-5-13
编辑：pawlo392 2019-5-13
Ok, I didn't see this:
fid=fopen(filename);
Should be:
fid=fopen(A);
But, Now I got:
Error using textscan
Unable to parse the format character vector at position 1 ==> %/s
Unsupported format specifier '%/'. See the documentation for TEXTSCAN for
supported formats.
Guillaume
Guillaume 2019-5-13
Well, yes as the error message says, %/s is not a valid format specifier. The / has no place there.

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采纳的回答

Jan
Jan 2019-5-13
编辑：Jan 2019-5-13
Use uigetfile instead of an fragile input command. But even then you should check the output of fopen:
[fid, msg] = fopen(filename);
assert(fid ~= -1, 'Cannot open file %s: %s', filename, msg);
Instead of using the cells created by textscan, the import as char vector is easier:
[filename, pathname] = uigetfile;
file = fullfile(filepath, filename);
word = input('Searched word : ', 's');
str = fileread(file);
str(ismember(str, '.,:!"''?')) = ' '; % Replace punctuation
str = [' ', str, ' '];
match = strfind(str, [' ', word, ' ']);
count = numel(match);

更多回答（1 个）

Image Analyst
Image Analyst 2019-5-13
Instead of
A=input(filename,'s');
try this:
[folder, baseFileName] = uigetfile('*.*');
filename = fullfile(folder, baseFileName)

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