How can I check in an arbitrary vector that the first index is greater than the next index and so on?
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I'm thinking that I can make a for lp that runs through the length of the input vector and checks if the max is greater than the minimum for each index. Then make a new vector with only the inversions and finally take the length of that vector. I have this written this code so far:
function inv = inversions(board)
% Input vector
BR = [15 2 1 12 8 5 6 11 4 9 10 7 3 14 13];
L = length(BR);
for i = 1:L
if max(BR(i)) > min(BR(i))
inv
end
1 个评论
Adam
2019-6-26
编辑:Adam
2019-6-26
You need to check each value against the preceeding value. BR(i) is a scalar so its min and max are both equal to the value itself and will not tell you anything about the sequence of numbers.
You also need to keep a running counter of cases where there is an inversion, which you would initialise to 0 before any loop.
回答(2 个)
Jan
2019-6-26
编辑:Jan
2019-6-26
BR = [15 2 1 12 8 5 6 11 4 9 10 7 3 14 13]
Now you want to determine, if an element is larger or smaller than the former one:
BR(2:end) > BR(1:end-1)
Or alternatively:
diff(BR) > 0
Now you get a sequence of TRUE and FALSE values, which are treated as 1 and 0 such that a sum command counts them.
0 个评论
Omer Badreldin
2019-6-26
另请参阅
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