Variable is not fully defined on some execution paths.

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Poornima Asuti
Poornima Asuti 2019-7-17
评论： Poornima Asuti 2019-7-18
I have written a matlab code for dividing an image into smaller parts. While using the HDL coder, I am getting an error "Variable 'tcell2{1, 1}' is not fully defined on some execution paths".
%%croping the image and storing the values in a cell
t=1;
tcell2=cell(10,10);
for y=0:100:900
s=1;
for z=0:100:900
final=imcrop(pic2,[(z+1) (y+1) width height]);
tcell2{t,s}=final;
s=s+1;
end
t=t+1;
end
%%taking mean of the elements in a matrix and storing values in a cell
for i=1:1:10
for l=1:1:10
mtcell2{i,l}=mean2(tcell2{i,l});%% getting an error over here
end
end
  2 个评论
KALYAN ACHARJYA
KALYAN ACHARJYA 2019-7-17
编辑：KALYAN ACHARJYA 2019-7-17
%%croping the image and storing the values in a cell and mean of each cell element
If this is the objective, then you can do it by more simpler way.

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采纳的回答

Jan
Jan 2019-7-17
编辑：Jan 2019-7-17
Does this help?
tcell2 = cell(10,10);
for t = 1:10
for s = 1:10
tcell2{t,s} = imcrop(pic2, ...
[(t-1)*100 + 1, (s-1)*100 + 1, width, height]);
end
end

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