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splitting a array at defined interval

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strunack
strunack 2013-4-9
I have a array c of 276 elements. I want to split it into 3 separate array. The number of elements in each of these three array is within the array c itself.
vind=c(find(c>=10)) %gives me
vind =
45 45 183
I have to split the array c into three arrays with number of elements as 45, 45 and 183 respectively excluding the position of these three numbers. Pls suggest how it can be done.
with thanks

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采纳的回答

Cedric
Cedric 2013-4-9
编辑：Cedric 2013-4-9
Alternatively:
loc = find(c >= 10) ;
vind = c(loc) ;
c(loc) = [] ;
out = mat2cell(c, 1, vind) ;
  1 个评论
strunack
strunack 2013-4-10
I accepted this answer, because its very logical, clean and simple way to split without any loop. I could do the same with loop but in a rather inefficient way than Azzi's answer. Thanks to him too.

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更多回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-4-9
ii=1;
for k=1:numel(vind)
jj=vind(k)
out{k}=c(ii:jj)
ii=jj+1;
end
  1 个评论
Jan
Jan 2013-4-9
编辑：Jan 2013-4-9
Please add some code for the pre-allocation also. Otherwise we have to answer corresponding question next week again. Thanks.
As far as I understand, the OP wants the part from ii to jj-1 only.

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