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Strings with changing length and cases

3 次查看（过去 30 天）
JP
JP 2013-6-19
Hi, Im trying to make the following code work and it just wont seem to do what I want. NOTE - The string length of my variable is changing so for different cases I want a different interval.
Astr = '123456789'
switch Astr
case strcmp(Astr([2:4,5:7]), '234567' )
x = 5
case strcmp(Astr([3:6,6:8]), '789123' )
x = 6
case strcmp(Astr([1:3,4:6]), '912345' )
x = 7
otherwise
x = 8
end
I think it has to do with the way Im defining the string values, it keeps outputting x = 8 (the otherwise case). Please let me know how to fix thanks!

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2013-6-19
It's more appropriate to use IF statement
Astr = '123456789'
if isequal(Astr([2:4,5:7]), '234567' )
x = 5
elseif isequal(Astr([3:6,6:8]), '789123' )
x = 6
elseif isequal(Astr([1:3,4:6]), '912345' )
x = 7
else
x = 8
end

更多回答（2 个）

Iain
Iain 2013-6-19
Assuming that you've shown us "everything". Theres a better way:
x = 8 - (Astr(3) == '2') - 2*(Astr(3) == '7') - 3*(Astr(3) == '3');
  2 个评论
JP
JP 2013-6-19
Well I havent shown everything...I was just using this as a simpler example for a more complex code Im working on....
Iain
Iain 2013-6-19
Azzi's solution is correct, but it will be easy to get lost in it, and make logical errors.

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Jan
Jan 2013-6-19
This case can never happen:
strcmp(Astr([3:6,6:8]), '789123' )
One string has 7 character with a repeated sixth element, while the other string has 6 characters only without a repetition.

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