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Re-arranging huge martix

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Morgan
Morgan 2012-3-21
Hi guys, spent long time trying to figure out how to rearange the matrix that I have, what am having is the following martix
A= [ x1 y1 x2 y2 x3 y3 ; x4 y4 x5 y5 x6 y6]
am trying to arrange my matrix into the following form B = [x1 y1 ; x2 y2 ; x3 y3 ; ....]
my original matrix is (10,1300) am trying to convert it to (6500,2)
i have tried to use for loop but it did not work out
here is my script
A = input('enter mat>');
rowA= size(A,1);
colA= size(A,2);
n=numel(A)/2;
for i=1:1:rowA
for j=1:2:colA-1
B = A(i,[j,j+1])
%continue
end
end
please i need something more efficient and faster than for loops!
Thanks
Morgan

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采纳的回答

Jan
Jan 2012-3-21
B = transpose(reshape(transpose(A), 2, []));
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Geoff
Geoff 2012-3-22
It's pretty huge, considering you have to type the whole thing in at that prompt. ;-)
Jan
Jan 2012-3-22
You can let the java robot do the typing for you. Then it is small again.

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